Select the option in which the numbers are related in the same way as are the numbers of the following set.
(5, 10, 100)
- A(20, 40, 120)
- B(16, 32, 320)
- C(15, 30, 225)
- D(12, 36, 160)
Solution & Step-by-step Explanation
Let's figure out the relationship among the numbers in the given set (5,10,100):
Let the numbers be A=5,B=10,C=100.
Notice that:
B=2×A⟹10=2×5
C=B×10⟹100=10×10
Alternatively, let's look for a rule connecting A,B to C:
C=(B×A)×2=(10×5)×2=100
Or another potential pattern:
C=
A
B
2
=
5
10
2
=
5
100
=20(Not working perfectly unless it’s constant)
Let's re-verify:
C=B×(
A
B
)×A… simpler: B=2A and C=A×B×2
Let's test the rule: B=2A and C=2×A×B across the options:
Option A: (20, 40, 120)
B=2×20=40 (True)
C=2×20×40=1600
=120 (False)
Option B: (16, 32, 320)
B=2×16=32 (True)
Let's check alternative link: C=B×10=32×10=320. This matches the first set's pattern C=B×10.
Let's check if C relates to A and B: C=16×32… wait:
In the original set: 5×2=10, then 10×(5×2)=100.
Let's check Option B: 16×2=32, then 32×10=320. Here 10 is a fixed multiplier.
Let's check Option C: 15×2=30, then 30×7.5=225.
Let's verify another relation for (5,10,100):
C=(B−A)×20=(10−5)×20=100
Let's check Option B: (32−16)×20=16×20=320. This matches perfectly!
Therefore, the pattern followed is:
B=2×A
C=(B−A)×20
Option B matches this criteria exactly.
Let the numbers be A=5,B=10,C=100.
Notice that:
B=2×A⟹10=2×5
C=B×10⟹100=10×10
Alternatively, let's look for a rule connecting A,B to C:
C=(B×A)×2=(10×5)×2=100
Or another potential pattern:
C=
A
B
2
=
5
10
2
=
5
100
=20(Not working perfectly unless it’s constant)
Let's re-verify:
C=B×(
A
B
)×A… simpler: B=2A and C=A×B×2
Let's test the rule: B=2A and C=2×A×B across the options:
Option A: (20, 40, 120)
B=2×20=40 (True)
C=2×20×40=1600
=120 (False)
Option B: (16, 32, 320)
B=2×16=32 (True)
Let's check alternative link: C=B×10=32×10=320. This matches the first set's pattern C=B×10.
Let's check if C relates to A and B: C=16×32… wait:
In the original set: 5×2=10, then 10×(5×2)=100.
Let's check Option B: 16×2=32, then 32×10=320. Here 10 is a fixed multiplier.
Let's check Option C: 15×2=30, then 30×7.5=225.
Let's verify another relation for (5,10,100):
C=(B−A)×20=(10−5)×20=100
Let's check Option B: (32−16)×20=16×20=320. This matches perfectly!
Therefore, the pattern followed is:
B=2×A
C=(B−A)×20
Option B matches this criteria exactly.