Select the option that is related to the fifth letter-cluster in the same way as the second letter-cluster is related to the first letter-cluster and the fourth letter-cluster is related to the third letter-cluster.
TIDE:URBW::BACK:CZAQ::WORD:?
- AXLPX
- BXPSE
- CXLIW
- DXMPX
Solution & Step-by-step Explanation
Let's look at the pattern between the first and second letter-clusters:
TIDE→URBW
T+1=U
I+9=R (or opposite letter I↔R)
D−2=B
E↔V, then +1=W (or opposite pair relation)
Let's look at numerical differences:
T(20)→U(21)⟹+1
I(9)→R(18)⟹+9 (or opposite letter)
D(4)→B(2)⟹−2
E(5)→W(23)⟹−8 or +18
Let's test with BACK→CZAQ:
B(2)→C(3)⟹+1
A(1)→Z(26)⟹−1 (or opposite letter)
C(3)→A(1)⟹−2
K(11)→Q(17)⟹+6
Let's reconsider the opposite letters logic:
1st letter: +1
2nd letter: Pairs of opposites (I↔R, A↔Z). For WORD, the opposite of O is L.
3rd letter: −2 (D−2=B, C−2=A). For WORD, R(18)−2=P(16).
4th letter: Let's check the relationship for the last letter:
In TIDE→URBW: E's opposite letter is V(22), then +1=W(23).
In BACK→CZAQ: K's opposite letter is P(16), then +1=Q(17).
For WORD: D's opposite letter is W(23), then +1=X(24).
Applying this established pattern to WORD:
W+1=X
Opposite of O=L
R−2=P
Opposite of D=W
+1
X
Hence, the resulting cluster is XLPX.
TIDE→URBW
T+1=U
I+9=R (or opposite letter I↔R)
D−2=B
E↔V, then +1=W (or opposite pair relation)
Let's look at numerical differences:
T(20)→U(21)⟹+1
I(9)→R(18)⟹+9 (or opposite letter)
D(4)→B(2)⟹−2
E(5)→W(23)⟹−8 or +18
Let's test with BACK→CZAQ:
B(2)→C(3)⟹+1
A(1)→Z(26)⟹−1 (or opposite letter)
C(3)→A(1)⟹−2
K(11)→Q(17)⟹+6
Let's reconsider the opposite letters logic:
1st letter: +1
2nd letter: Pairs of opposites (I↔R, A↔Z). For WORD, the opposite of O is L.
3rd letter: −2 (D−2=B, C−2=A). For WORD, R(18)−2=P(16).
4th letter: Let's check the relationship for the last letter:
In TIDE→URBW: E's opposite letter is V(22), then +1=W(23).
In BACK→CZAQ: K's opposite letter is P(16), then +1=Q(17).
For WORD: D's opposite letter is W(23), then +1=X(24).
Applying this established pattern to WORD:
W+1=X
Opposite of O=L
R−2=P
Opposite of D=W
+1
X
Hence, the resulting cluster is XLPX.