Select the option that is related to the fifth letter cluster in the same way as the second letter cluster is related to the first letter cluster and the fourth letter cluster is related to the third letter cluster.
BASIC : GEVKD :: TABLE : YEENF :: COULD : ?
- AHRXNE
- BHSYNE
- CITYMF
- DHSXNE
Solution & Step-by-step Explanation
The logic followed here is:
Divide the 5-letter word into its first 2 letters, middle letter, and last 2 letters.
For the first two letters, add +1 to their positional values and reverse their order.
For the middle letter, add +4 to its positional value.
For the last two letters, add +1 to their positional values and reverse their order.
Let's check BASIC : GEVKD:
First two letters: BA → +1 → CB → reverse → BC (Wait, let's look closer at the absolute pattern mapping: B→G, A→E, S→V, I→K, C→D?)
Let's analyze positional offsets:
B(2)+5=G(7)
A(1)+4=E(5)
S(19)+3=V(22)
I(9)+2=K(11)
C(3)+1=D(4)
Let's check if this simple positional addition works for TABLE : YEENF:
T(20)+5=Y(25)
A(1)+4=E(5)
B(2)+3=E(5)
L(12)+2=N(14)
E(5)+1=F(6)
The pattern is strictly adding +5,+4,+3,+2,+1 to the consecutive positions.
Applying the same pattern to COULD:
C(3)+5=H(8)
O(15)+4=S(19)
U(21)+3=X(24)
L(12)+2=N(14)
D(4)+1=E(5)
Thus, the required cluster is HSXNE.
Divide the 5-letter word into its first 2 letters, middle letter, and last 2 letters.
For the first two letters, add +1 to their positional values and reverse their order.
For the middle letter, add +4 to its positional value.
For the last two letters, add +1 to their positional values and reverse their order.
Let's check BASIC : GEVKD:
First two letters: BA → +1 → CB → reverse → BC (Wait, let's look closer at the absolute pattern mapping: B→G, A→E, S→V, I→K, C→D?)
Let's analyze positional offsets:
B(2)+5=G(7)
A(1)+4=E(5)
S(19)+3=V(22)
I(9)+2=K(11)
C(3)+1=D(4)
Let's check if this simple positional addition works for TABLE : YEENF:
T(20)+5=Y(25)
A(1)+4=E(5)
B(2)+3=E(5)
L(12)+2=N(14)
E(5)+1=F(6)
The pattern is strictly adding +5,+4,+3,+2,+1 to the consecutive positions.
Applying the same pattern to COULD:
C(3)+5=H(8)
O(15)+4=S(19)
U(21)+3=X(24)
L(12)+2=N(14)
D(4)+1=E(5)
Thus, the required cluster is HSXNE.