Select the option that is related to the fifth letter-cluster in the same way as the second letter-cluster is related to the first letter-cluster and the fourth letter-cluster is related to the third letter-cluster.
SONG : VQOT :: RIDE : UKEV :: BEAR : ?
- AEGBI
- BCGDI
- CEHDU
- DYVZI
Solution & Step-by-step Explanation
Let's analyze the relationship between the pairs of letter clusters:
First Pair: SONG : VQOT
S (+3) → V
O (+2) → Q
N (+1) → O
G (+1) → T (Wait, G is 7 and T is 20. Let's look closer at the pattern. Alternatively, G is the 7th letter from the start, and T is the 7th letter from the end. They are opposite letters).
Let's check the position values:
S(19) + 3 = V(22)
O(15) + 2 = Q(17)
N(14) + 1 = O(15)
G(7) → Opposite letter is T(20)
Second Pair: RIDE : UKEV
R(18) + 3 = U(21)
I(9) + 2 = K(11)
D(4) + 1 = E(5)
E(5) → Opposite letter is V(22)
Applying the same logic to BEAR:
B(2) + 3 = E(5)
E(5) + 2 = G(7)
A(1) + 1 = B(2)
R(18) → Opposite letter is I(9)
Hence, the resulting cluster is EGBI.
First Pair: SONG : VQOT
S (+3) → V
O (+2) → Q
N (+1) → O
G (+1) → T (Wait, G is 7 and T is 20. Let's look closer at the pattern. Alternatively, G is the 7th letter from the start, and T is the 7th letter from the end. They are opposite letters).
Let's check the position values:
S(19) + 3 = V(22)
O(15) + 2 = Q(17)
N(14) + 1 = O(15)
G(7) → Opposite letter is T(20)
Second Pair: RIDE : UKEV
R(18) + 3 = U(21)
I(9) + 2 = K(11)
D(4) + 1 = E(5)
E(5) → Opposite letter is V(22)
Applying the same logic to BEAR:
B(2) + 3 = E(5)
E(5) + 2 = G(7)
A(1) + 1 = B(2)
R(18) → Opposite letter is I(9)
Hence, the resulting cluster is EGBI.