Select the option that is related to the third letter-cluster in the same way as the second letter-cluster is related to the first letter-cluster.BENGAL : ODJQHE :: LAUNCH : ?

Let's determine the relation between BENGAL and ODJQHE:Split the word into two halves: BEN and GAL.Reverse the first half: BEN $\to$ NEBReverse the second half: GAL $\to$ LAGNow add $+1$ to each letter of the reversed segments:$\text{N}+1=\text{O}$$\text{E}+1=\text{F}$ (Let's check if the pattern matches ODJQHE)Let's re-examine:$\text{B}\to \text{O}$? No, let's look at cross coding:$\text{B}+3=\text{E}$ (last letter)$\text{E}+3=\text{H}$ (fifth letter)$\text{N}+3=\text{Q}$ (fourth letter)$\text{G}+3=\text{J}$ (third letter)$\text{A}+3=\text{D}$ (second letter)$\text{L}+3=\text{O}$ (first letter)Let's check if this matches ODJQHE in reverse order:$\text{L}(12)+3=15\to \text{O}$$\text{A}(1)+3=4\to \text{D}$$\text{G}(7)+3=10\to \text{J}$$\text{N}(14)+3=17\to \text{Q}$$\text{E}(5)+3=8\to \text{H}$$\text{B}(2)+3=5\to \text{E}$ The complete string formed is ODJQHE. The pattern is reversing the entire word and adding $+3$ to each letter.Applying the same pattern to LAUNCH:Reverse of LAUNCH is HCNUAL.Now, add $+3$ to each letter:$\text{H}+3=8+3=11\to \text{K}$$\text{C}+3=3+3=6\to \text{F}$$\text{N}+3=14+3=17\to \text{Q}$$\text{U}+3=21+3=24\to \text{X}$$\text{A}+3=1+3=4\to \text{D}$$\text{L}+3=12+3=15\to \text{O}$ The resulting code is KFQXDO.