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Select the option that represents the letters that, when sequentially placed from left to right in the blanks, will complete the letter series.
r_m_s_t_i_m s s_r i m_ _s t

  1. A
    i m s r m t m s
  2. B
    i m s r s t s s
  3. C
    i s m r m t m s
  4. D
    i m s r t t m s

Solution & Step-by-step Explanation

Let's count the total number of characters in the given sequence:
r _ m _ s _ t _ i _ m s s _ r i m _ _ s t
Total length = 22 or can be broken down based on a recurring term.

Let's look closely at the letters present: r, i, m, s, t.
Notice the substring r i m [ ] s t. This suggests the repeating unit is the word rimsst or rimsst containing 6 blocks.

Let's try breaking the pattern down into blocks of 6 letters:

r [i] m [s] s [t] → r i m s s t

_ i _ m s s → if it matches r i m s s t, then it is [r] i [m] s s [t]

_ r i m _ _ s t → let's look at the remaining characters: r i m s s t repeated.

Let's re-verify with a consistent block pattern:
The repeating group is r i m s s t.

r [i] m [s] s [t]

[r] i [m] s s [t]

r i m [s] [s] t (or matching up the exact blanks given)

Let's map it explicitly to the blanks:
r [i] m [s] s [t] i [m] s s [r] i m [s] [s] t
Let's see if this lines up with the original question blanks:
Original: r _ m _ s _ t _ i _ m s s _ r i m _ _ s t
Let's check the options for the positions:
By placing option A elements: i, m, s, r, m, t, m, s
r [i] m [m] s [s] t [r] i [m] m s s [t] r i m [m] [s] s t → Does not form uniform words.

Let's try pattern rimsst:
If the word is r i m s s t:
r [i] m [s] s [t] (6 letters)
[r] i [m] s s [t] (6 letters) → Wait, the question has t _ i _ m s s _ r i m _ _ s t
Let's trace it carefully:
Letters: r, _, m, _, s, _, t, _, i, _, m, s, s, _, r, i, m, _, _, s, t
Total positions = 21 letters.
Let's divide into groups of 7: r _ m _ s _ t | _ i _ m s s _ | r i m _ _ s t

Comparing group 1 and group 3:
Group 1: r _ m _ s _ t
Group 3: r i m _ _ s t
This implies the pattern is r i m s s s t or similar.
Let's check:
Group 1: r [i] m [s] s [s] t → r i m s s s t
Group 2: [r] i [m] s s s [t] → r i m s s s t
Group 3: r i m [s] [s] s t → r i m s s s t

The sequentially filled letters are:
i, s, m, r, m, t, m, s

Let's check Option C: i s m r m t m s
This perfectly matches our derived blank fills.

Practice this question

Try it yourself before checking the explanation above.

Select the option that represents the letters that, when sequentially placed from left to right in the blanks, will complete the letter series.
r_m_s_t_i_m s s_r i m_ _s t
A
i m s r m t m s
B
i m s r s t s s
C
i s m r m t m s
D
i m s r t t m s

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