Select the related word/letters/number from the given alternatives.
DB : IC :: YE : ?
- AFJ
- BJF
- CTH
- DWL
Solution & Step-by-step Explanation
Let's look at the positional values of letters in the English alphabet (A=1,B=2,…,Z=26).
For DB : IC:
D=4, B=2. Squaring the position of B gives 2
2
=4, which corresponds to D. Alternatively, looking at the mapping DB→IC:
D(4)→I(9)⇒+5
B(2)→C(3)⇒+1
Let's check if this simple positional addition applies to YE:
Y=25, E=5.
If we use numerical relationships directly:
In DB, D=4 and B=2, notice that 2
2
=4 (i.e., B
2
=D).
In IC, I=9 and C=3, notice that 3
2
=9 (i.e., C
2
=I).
In YE, Y=25 and E=5, notice that 5
2
=25 (i.e., E
2
=Y).
Following this logic, the missing pair must satisfy (Second Letter)
2
=First Letter.
Let's test the options:
Option A: FJ →F=6,J=10. 10
2
=6.
Option B: JF →J=10,F=6. 6
2
=36≡10(mod26). Since 36−26=10, the 36
th
letter is indeed J. Thus, F
2
=6
2
=36→J.
Option C: TH →T=20,H=8. 8
2
=64≡12(mod26)
=20.
Option D: WL →W=23,L=12. 12
2
=144≡14(mod26)
=23.
Therefore, JF perfectly satisfies the rule (Second Letter)
2
=First Letter.
For DB : IC:
D=4, B=2. Squaring the position of B gives 2
2
=4, which corresponds to D. Alternatively, looking at the mapping DB→IC:
D(4)→I(9)⇒+5
B(2)→C(3)⇒+1
Let's check if this simple positional addition applies to YE:
Y=25, E=5.
If we use numerical relationships directly:
In DB, D=4 and B=2, notice that 2
2
=4 (i.e., B
2
=D).
In IC, I=9 and C=3, notice that 3
2
=9 (i.e., C
2
=I).
In YE, Y=25 and E=5, notice that 5
2
=25 (i.e., E
2
=Y).
Following this logic, the missing pair must satisfy (Second Letter)
2
=First Letter.
Let's test the options:
Option A: FJ →F=6,J=10. 10
2
=6.
Option B: JF →J=10,F=6. 6
2
=36≡10(mod26). Since 36−26=10, the 36
th
letter is indeed J. Thus, F
2
=6
2
=36→J.
Option C: TH →T=20,H=8. 8
2
=64≡12(mod26)
=20.
Option D: WL →W=23,L=12. 12
2
=144≡14(mod26)
=23.
Therefore, JF perfectly satisfies the rule (Second Letter)
2
=First Letter.