Select the set in which the numbers are related in the same way as are the numbers of the following set.
(NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into its constituent digits.)
(7, 1, 72)
(5, 2, 18)
- A(4, 2, 12)
- B(2, 1, 6)
- C(7, 5, 45)
- D(3, 1, 8)
Solution & Step-by-step Explanation
Let's find the logic connecting the numbers (a,b,c) in the given sets:
For (7,1,72):
(7+1)×9=8×9=72
Or another logic:
(7
2
−1
2
)=48×1.5=72
Let's try another one:
(7+1)×(7−1)=8×6=48→not 72.
Let's check the cube/square combinations:
(a+b)×(a−b)×something?
What about (a
3
−b
3
) or (a+b) relations?
Let's look at (5,2,18):
Using the first logic: (5+2)×9=7×9=63
=18. So this is wrong.
Let's find another pattern:
For (7,1,72):
(7+1)
2
=64+8=72⟹(a+b)
2
+(a+b)=72?
Let's check for (5,2,18):
(5+2)
2
=49
=18.
Let's try:
c=(a−b)×something
For (7,1,72): 7−1=6; 72/6=12. So, (a−b)×12=72.
Let's test this with (5,2,18):
5−2=3; 18/3=6. Here it is multiplied by 6 instead of 12.
Notice that 12=2×6, and 6=2×3.
So the multiplier is 2×(a−b)?
Let's check: c=2×(a−b)
2
For (7,1,72): 2×(7−1)
2
=2×6
2
=2×36=72.
For (5,2,18): 2×(5−2)
2
=2×3
2
=2×9=18.
The logic is perfectly consistent:
c=2×(a−b)
2
Now let's check the options with this formula:
Option A: (4,2,12)→2×(4−2)
2
=2×2
2
=8
=12
Option B: (2,1,6)→2×(2−1)
2
=2×1
2
=2
=6
Option C: (7,5,45)→2×(7−5)
2
=2×2
2
=8
=45
Option D: (3,1,8)→2×(3−1)
2
=2×2
2
=2×4=8.
Option D fits the logic perfectly.
For (7,1,72):
(7+1)×9=8×9=72
Or another logic:
(7
2
−1
2
)=48×1.5=72
Let's try another one:
(7+1)×(7−1)=8×6=48→not 72.
Let's check the cube/square combinations:
(a+b)×(a−b)×something?
What about (a
3
−b
3
) or (a+b) relations?
Let's look at (5,2,18):
Using the first logic: (5+2)×9=7×9=63
=18. So this is wrong.
Let's find another pattern:
For (7,1,72):
(7+1)
2
=64+8=72⟹(a+b)
2
+(a+b)=72?
Let's check for (5,2,18):
(5+2)
2
=49
=18.
Let's try:
c=(a−b)×something
For (7,1,72): 7−1=6; 72/6=12. So, (a−b)×12=72.
Let's test this with (5,2,18):
5−2=3; 18/3=6. Here it is multiplied by 6 instead of 12.
Notice that 12=2×6, and 6=2×3.
So the multiplier is 2×(a−b)?
Let's check: c=2×(a−b)
2
For (7,1,72): 2×(7−1)
2
=2×6
2
=2×36=72.
For (5,2,18): 2×(5−2)
2
=2×3
2
=2×9=18.
The logic is perfectly consistent:
c=2×(a−b)
2
Now let's check the options with this formula:
Option A: (4,2,12)→2×(4−2)
2
=2×2
2
=8
=12
Option B: (2,1,6)→2×(2−1)
2
=2×1
2
=2
=6
Option C: (7,5,45)→2×(7−5)
2
=2×2
2
=8
=45
Option D: (3,1,8)→2×(3−1)
2
=2×2
2
=2×4=8.
Option D fits the logic perfectly.