Statement-1 : The point $A(1,0,7)$ is the mirror image of the point $B(1,6,3)$ in the line $\frac{x-1}{0}=\frac{y-1}{2}=\frac{z-2}{3}$.Statement-2 : The line $\frac{x-1}{0}=\frac{y-1}{2}=\frac{z-2}{3}$ bisects the line segment joining $A(1,0,7)$ and $B(1,6,3)$.

Midpoint of $AB$: $M=(\frac{1+1}{2},\frac{0+6}{2},\frac{7+3}{2})=(1,3,5)$.Check if $M$ lies on the line:$\frac{1-1}{0}=\text{indet}$, $\frac{3-1}{2}=1$, $\frac{5-2}{3}=1$.Since $1=1$ and the $x$ -coordinates match ($1-1=0$), $M$ lies on the line. Statement 2 is true.For Statement 1 to be true, $AB$ must also be perpendicular to the line.Direction vector of $AB$: ${\vec{V}}_{AB}=(1-1,6-0,3-7)=(0,6,-4)$.Direction vector of line: $\vec{L}=(0,2,3)$.Dot product: ${\vec{V}}_{AB}\cdot \vec{L}=0(0)+6(2)+(-4)(3)=12-12=0$.Since they are perpendicular and the midpoint lies on the line, $A$ is the mirror image of $B$.Statement 2 is true but bisecting is only one condition (perpendicularity is the other). However, in standard AIEEE logic, if both are true and S2 is a necessary condition, it's often linked. Let's verify standard answer: the perpendicular bisector is the definition of a mirror.