Statement I: The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole - dipole interactions.Statement II: The boiling points of aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding.
- ABoth Statement I and Statement II are correct.
- BBoth Statement I and Statement II are incorrect.
- CStatement I is correct but Statement II is incorrect.
- DStatement I is incorrect but Statement II is correct.
Solution & Step-by-step Explanation
1. Statement I is correct: The polar carbonyl group leads to dipole-dipole interactions, which are stronger than van der Waals forces in hydrocarbons, resulting in higher boiling points.2. Statement II is correct: Alcohols have strong intermolecular hydrogen bonding, which is absent in aldehydes and ketones. Thus, alcohols have much higher boiling points than aldehydes/ketones of similar mass.