Structure of a mixed oxide is cubic close-packed (c.c.p). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral - Chemistry MCQ Chemistry | ExamTest.live | ExamTest.live

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Structure of a mixed oxide is cubic close-packed (c.c.p). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B . The formula of the oxide is:

A $AB_{2} O_{2}$
B $ABO_{2}$
C $A_{2} BO_{2}$
D $A_{2} B_{3} O_{4}$

Solution & Step-by-step Explanation

1. In a c.c.p lattice, if number of atoms (O^{2 -}) is Z = 4 :2. Octahedral voids = Z = 4 .3. Tetrahedral voids = 2 Z = 8 .4. Moles of A (divalent): \frac{1}{4} of tetrahedral voids = \frac{1}{4} \times 8 = 2 .5. Moles of B (monovalent): All octahedral voids = 4 .Ratio A : B : O = 2 : 4 : 4 = 1 : 2 : 2 .Formula: AB_{2} O_{2} .

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Structure of a mixed oxide is cubic close-packed (c.c.p). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B . The formula of the oxide is:

A

AB_{2} O_{2}

B

ABO_{2}

C

A_{2} BO_{2}

D

A_{2} B_{3} O_{4}

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