Study the following sequence of letters, digits and symbols carefully:
$$8\cdot \text{F W \$ Y }56\text{ G ? }71\text{ E N \# P }3\text{ @ J B }\Delta 4\text{ M R }92\text{ + K}$$

If the first seventeen elements are written in the reverse order followed by the next eleven elements, which element would be the fifth to the right of E?

Let's count and isolate the first 17 elements of the sequence:
$$\text{Elements 1 to 17: }[8,\cdot ,\text{F},\text{W},\$,\text{Y},5,6,\text{G},?,7,1,\text{E},\text{N},\#,\text{P},3]$$

Reversing these first 17 elements yields:

$$[3,\text{P},\#,\text{N},\mathbf{E},1,7,?,\text{G},6,5,\text{Y},\$,\text{W},\text{F},\cdot ,8]$$

The remaining 11 elements stay appended in their original relative structure afterwards. Looking at the position of $\text{E}$ in this newly reversed arrangement, let us find the 5th element to its right side:

* 1st right: 1
* 2nd right: 7
* 3rd right: ?
* 4th right: G
* 5th right: 6
Thus, the fifth element to the right of $\text{E}$ is $6$.