The amount of Rs 6,045 is divided into A, B and C in such a way that if 10 rupees is reduced from A's part, 15 rupees is reduced from B's part and 20 rupees is reduced from C's part. Then, the ratio of their parts will be 5:4:3. Find the initial part of B (in rupees).
- A2,015
- B2,000
- C1,985
- D2,250
Solution & Step-by-step Explanation
Total initial amount = Rs. 6,045
Total amount reduced = Rs. 10+Rs. 15+Rs. 20=Rs. 45
Remaining amount to be divided = 6045−45=Rs. 6000
The remaining amount is divided in the ratio 5:4:3.
Sum of ratio terms = 5+4+3=12
Remaining part of B =
12
4
×6000=Rs. 2000
Initial part of B = Remaining part of B + Reduced amount of B
Initial part of B = 2000+15=Rs. 2015
Total amount reduced = Rs. 10+Rs. 15+Rs. 20=Rs. 45
Remaining amount to be divided = 6045−45=Rs. 6000
The remaining amount is divided in the ratio 5:4:3.
Sum of ratio terms = 5+4+3=12
Remaining part of B =
12
4
×6000=Rs. 2000
Initial part of B = Remaining part of B + Reduced amount of B
Initial part of B = 2000+15=Rs. 2015