The area of a triangular plot, whose sides are 100m, 105m and 145m, is equal to a rectangular field, whose sides are in the ratio 7:10. The perimeter (in m) of the rectangular field is:
- A3405
- B3403
- C170
3
- D170
5
Solution & Step-by-step Explanation
First, let's find the area of the triangular plot using Heron's formula.
The sides are a=100m, b=105m, and c=145m.
The semi-perimeter (s) is:
s=
2
a+b+c
=
2
100+105+145
=
2
350
=175m
Now, compute the area (A
triangle
):
A
triangle
=
s(s−a)(s−b)(s−c)
A
triangle
=
175×(175−100)×(175−105)×(175−145)
A
triangle
=
175×75×70×30
A
triangle
=
(25×7)×(25×3)×(7×10)×(3×10)
A
triangle
=
25
2
×7
2
×3
2
×10
2
=25×7×3×10=5250m
2
The area of the rectangular field is equal to this triangular area. Let the sides of the rectangle be 7k and 10k:
Area of rectangle=7k×10k=70k
2
70k
2
=5250⟹k
2
=
70
5250
=75⟹k=
75
=5
3
The perimeter of the rectangular field is:
Perimeter=2(Length+Width)=2(10k+7k)=2(17k)=34k
Perimeter=34×5
3
=170
3
m
The sides are a=100m, b=105m, and c=145m.
The semi-perimeter (s) is:
s=
2
a+b+c
=
2
100+105+145
=
2
350
=175m
Now, compute the area (A
triangle
):
A
triangle
=
s(s−a)(s−b)(s−c)
A
triangle
=
175×(175−100)×(175−105)×(175−145)
A
triangle
=
175×75×70×30
A
triangle
=
(25×7)×(25×3)×(7×10)×(3×10)
A
triangle
=
25
2
×7
2
×3
2
×10
2
=25×7×3×10=5250m
2
The area of the rectangular field is equal to this triangular area. Let the sides of the rectangle be 7k and 10k:
Area of rectangle=7k×10k=70k
2
70k
2
=5250⟹k
2
=
70
5250
=75⟹k=
75
=5
3
The perimeter of the rectangular field is:
Perimeter=2(Length+Width)=2(10k+7k)=2(17k)=34k
Perimeter=34×5
3
=170
3
m