The average of 10 numbers is 30. If at the time of calculation one number was wrongly taken as 36 instead of 69, then what will be the correct average?
- A33
- B33.3
- C36
- D39
Solution & Step-by-step Explanation
Given:
Number of observations (n) =10
Incorrect Average =30
Incorrect Sum =30×10=300
Now, find the correction:
Wrong value taken =36
Correct value to be taken =69
Difference (Correction) =69−36=+33
Correct Sum =300+33=333
Correct Average =
n
Correct Sum
=
10
333
=33.3
Number of observations (n) =10
Incorrect Average =30
Incorrect Sum =30×10=300
Now, find the correction:
Wrong value taken =36
Correct value to be taken =69
Difference (Correction) =69−36=+33
Correct Sum =300+33=333
Correct Average =
n
Correct Sum
=
10
333
=33.3