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The correct IUPAC name of the compound
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  1. A
    -(1-ethylpropyl)hex- -ene
  2. B
    -Ethyl- -propylhex- -ene
  3. C
    -Ethyl- -ethenylheptane
  4. D
    -Ethyl- -propylhex- -ene

Solution & Step-by-step Explanation

1. Longest chain containing the double bond has 6 carbons (hex-1-ene).2. Numbering starts from the double bond end.3. Substituents are at position 3 (propyl) and position 4 (ethyl).4. Alphabetical order: Ethyl before Propyl.Name: 4-Ethyl-3-propylhex-1-ene.
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The correct IUPAC name of the compound
image
A
-(1-ethylpropyl)hex- -ene
B
-Ethyl- -propylhex- -ene
C
-Ethyl- -ethenylheptane
D
-Ethyl- -propylhex- -ene

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