The correct order of energies of molecular orbitals of N_2 molecule is: - Chemistry MCQ NEET 2023 2026 | ExamTest.live

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The correct order of energies of molecular orbitals of N_{2} molecule is:

A $σ 1 s < σ^{*} 1 s < σ 2 s < σ^{*} 2 s < (π 2 p_{x} = π 2 p_{y}) < σ 2 p_{z} < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}$
B $σ 1 s < σ^{*} 1 s < σ 2 s < σ^{*} 2 s < σ 2 p_{z} < (π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < π^{*} 2 p_{z}$
C $σ 1 s < σ^{*} 1 s < σ 2 s < σ^{*} 2 s < σ 2 p_{z} < σ^{*} 2 p_{z} < (π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y})$
D $σ 1 s < σ^{*} 1 s < σ 2 s < σ^{*} 2 s < (π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ 2 p_{z} < σ^{*} 2 p_{z}$

Solution & Step-by-step Explanation

For molecules with \leq 14 electrons (like N_{2}, C_{2}, B_{2}), due to s - p mixing, the σ 2 p_{z} orbital is higher in energy than the π 2 p orbitals.The sequence is: σ 1 s, σ^{*} 1 s, σ 2 s, σ^{*} 2 s, (π 2 p_{x} \approx π 2 p_{y}), σ 2 p_{z}, (π^{*} 2 p_{x} \approx π^{*} 2 p_{y}), σ^{*} 2 p_{z} .This matches Option A.

Try it yourself before checking the explanation above.

The correct order of energies of molecular orbitals of N_{2} molecule is:

σ 1 s < σ^{*} 1 s < σ 2 s < σ^{*} 2 s < (π 2 p_{x} = π 2 p_{y}) < σ 2 p_{z} < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}

σ 1 s < σ^{*} 1 s < σ 2 s < σ^{*} 2 s < σ 2 p_{z} < (π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < π^{*} 2 p_{z}

σ 1 s < σ^{*} 1 s < σ 2 s < σ^{*} 2 s < σ 2 p_{z} < σ^{*} 2 p_{z} < (π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y})

σ 1 s < σ^{*} 1 s < σ 2 s < σ^{*} 2 s < (π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ 2 p_{z} < σ^{*} 2 p_{z}

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