The correct order of increasing bond angles in the following triatomic species is:

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The correct order of increasing bond angles in the following triatomic species is:

A $NO_{2}^{+} < NO_{2} < NO_{2}^{-}$
B $NO_{2} < NO_{2}^{-} < NO_{2}^{+}$
C $NO_{2}^{-} < NO_{2} < NO_{2}^{+}$
D $NO_{2}^{+} < NO_{2}^{-} < NO_{2}$

Solution & Step-by-step Explanation

1. NO_{2}^{+} : s p hybridization, linear, angle 18 0^{\circ} .2. NO_{2} : One unpaired electron, bent, angle \approx 13 4^{\circ} .3. NO_{2}^{-} : One lone pair, bent, angle \approx 11 5^{\circ} .Order: NO_{2}^{-} < NO_{2} < NO_{2}^{+} .

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The correct order of increasing bond angles in the following triatomic species is:

NO_{2}^{+} < NO_{2} < NO_{2}^{-}

NO_{2} < NO_{2}^{-} < NO_{2}^{+}

NO_{2}^{-} < NO_{2} < NO_{2}^{+}

NO_{2}^{+} < NO_{2}^{-} < NO_{2}

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Chemical Bonding Bond Angle Species

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