The correct order of increasing bond angles in the following species is:

1. ${\text{Cl}}_2\text{O}$: $s{p}^3$ hybridization on oxygen, two lone pairs. Bond angle $\approx 111^{\circ }$.2. ${\text{ClO}}_2^{-}$: $s{p}^3$ hybridization on chlorine, two lone pairs. More repulsion than ${\text{Cl}}_2\text{O}$ due to central atom size and charge.3. ${\text{ClO}}_2$: Odd electron molecule, $s{p}^2$ hybridized. One unpaired electron and one lone pair. Repulsion from lone pairs is less than in ${\text{ClO}}_2^{-}$. Angle $\approx 118^{\circ }$.Order: ${\text{ClO}}_2^{-}<{\text{Cl}}_2\text{O}<{\text{ClO}}_2$.