The correct sequence which shows decreasing order of the ionic radii of the elements is: - Chemistry MCQ AIEEE 2026 | ExamTest.live | ExamTest.live

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The correct sequence which shows decreasing order of the ionic radii of the elements is:

A $Al^{3 +} > Mg^{2 +} > Na^{+} > F^{-} > O^{2 -}$
B $Na^{+} > Mg^{2 +} > Al^{3 +} > O^{2 -} > F^{-}$
C $Na^{+} > F^{-} > Mg^{2 +} > O^{2 -} > Al^{3 +}$
D $O^{2 -} > F^{-} > Na^{+} > Mg^{2 +} > Al^{3 +}$

Solution & Step-by-step Explanation

These are isoelectronic species (all have 10 electrons). For isoelectronic species, the ionic radius decreases as the atomic number (nuclear charge) increases.Atomic numbers: O (8), F (9), Na (11), Mg (12), Al (13) .Order of radius: O^{2 -} > F^{-} > Na^{+} > Mg^{2 +} > Al^{3 +} .

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The correct sequence which shows decreasing order of the ionic radii of the elements is:

A

Al^{3 +} > Mg^{2 +} > Na^{+} > F^{-} > O^{2 -}

B

Na^{+} > Mg^{2 +} > Al^{3 +} > O^{2 -} > F^{-}

C

Na^{+} > F^{-} > Mg^{2 +} > O^{2 -} > Al^{3 +}

D

O^{2 -} > F^{-} > Na^{+} > Mg^{2 +} > Al^{3 +}

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Periodic Properties Ionic Radius

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