The cost price of two articles A and B is the same. Article A is sold at a loss of 24% and article B is sold for Rs. 270 more than the selling price of A. If the net profit by selling both the articles is 12%, then what is the selling price (in Rs.) of article B?

Let the cost price of each article A and B be x.
Total cost price of both articles = 2x.

Article A is sold at a loss of 24%:

SP
A
​
=x×(1−0.24)=0.76x
Article B is sold for Rs. 270 more than SP
A
​
:

SP
B
​
=0.76x+270
The net profit on both articles is 12%:

Total SP=2x×1.12=2.24x
Also, Total SP=SP
A
​
+SP
B
​
:

2.24x=0.76x+(0.76x+270)
2.24x=1.52x+270
2.24x−1.52x=270
0.72x=270⟹x=
0.72
270
​
=375
So, the cost price of each article is Rs. 375.
Now, the selling price of article B (SP
B
​
):

SP
B
​
=0.76(375)+270=285+270=Rs. 555