The current population of a town is 120000 . If the population increases by 10\% every year, then the population of the town after three years will be - Quantitative Aptitude MCQ Competitive Exam 2026 | ExamTest.live

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The current population of a town is 120000 . If the population increases by 10% every year, then the population of the town after three years will be

Solution & Step-by-step Explanation

Population growth can be calculated using the compound interest formula: P_{n} = P_{0} \times (1 + \frac{R}{100})^{n} Given: * Initial population (P_{0}) = 120000 * Annual growth rate (R) = 10% * Time (n) = 3 years Substitute the given values: P_{3} = 120000 \times (1 + \frac{10}{100})^{3} P_{3} = 120000 \times (1.1)^{3} P_{3} = 120000 \times 1.331 P_{3} = 120 \times 1331 = 159720

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The current population of a town is 120000 . If the population increases by 10% every year, then the population of the town after three years will be

125550

162900

134650

159720

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