The density (in g mL^-1 ) of a 3.60 M sulphuric acid solution that is 29\% H_2SO_4 (Molar mass = 98 g mol^-1 ) by mass will be: - Chemistry MCQ AIEEE 2007 2026 | ExamTest.live

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The density (in g mL^{- 1}) of a 3.60 M sulphuric acid solution that is 29% H_{2} SO_{4} (Molar mass = 98 g mol^{- 1}) by mass will be:

Solution & Step-by-step Explanation

Molarity (M) is related to mass percentage (x %) and density (d) by the formula: M = \frac{x \times d \times 10}{Molar Mass} Given: M = 3.60 x = 29 Molar Mass = 98 $ 3.60 = \frac{29 \times d \times 10}{98} $ d = \frac{3.60 \times 98}{290} d = \frac{352.8}{290} \approx 1.2165 g mL^{- 1} The density is approximately 1.22 g mL^{- 1} .

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The density (in g mL^{- 1}) of a 3.60 M sulphuric acid solution that is 29% H_{2} SO_{4} (Molar mass = 98 g mol^{- 1}) by mass will be:

1.64

1.88

1.22

1.45

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