The density of a solution prepared by dissolving 120 g of urea (mol. mass = 60 u ) in 1000 g of water is 1.15 g/mL . The molarity of this solution is: - Chemistry MCQ AIEEE 2012 2026 | ExamTest.live

mediumMCQAIEEE 20122026Chemistry

1 mark

The density of a solution prepared by dissolving 120 g of urea (mol. mass = 60 u) in 1000 g of water is 1.15 g/mL . The molarity of this solution is:

Solution & Step-by-step Explanation

Moles of urea = \frac{120}{60} = 2 mol .Total mass of solution = Mass of solute + Mass of solvent = 120 + 1000 = 1120 g .Volume of solution = \frac{Mass}{Density} = \frac{1120 g}{1.15 g/mL} \approx 973.91 mL = 0.9739 L .Molarity = \frac{Moles}{Volume in L} = \frac{2}{0.9739} \approx 2.05 M .

Try it yourself before checking the explanation above.

The density of a solution prepared by dissolving 120 g of urea (mol. mass = 60 u) in 1000 g of water is 1.15 g/mL . The molarity of this solution is:

0.50 M

1.78 M

1.02 M

2.05 M

Practice with timed mock tests and track your performance across Chemistry.