The diameter of a circle is equal to the side of the square. What is the area of the square if the area of the circle is 49πsq cm?
- A196sq cm
- B154sq cm
- C124sq cm
- D98sq cm
Solution & Step-by-step Explanation
Let the radius of the circle be r.
Given area of the circle = 49π:
πr
2
=49π⟹r
2
=49⟹r=7cm
Diameter of the circle (d) = 2r=2×7=14cm.
Since the side of the square (a) is equal to the diameter of the circle:
a=14cm
Area of the square=a
2
=14
2
=196sq cm
Given area of the circle = 49π:
πr
2
=49π⟹r
2
=49⟹r=7cm
Diameter of the circle (d) = 2r=2×7=14cm.
Since the side of the square (a) is equal to the diameter of the circle:
a=14cm
Area of the square=a
2
=14
2
=196sq cm