The displacement of an object attached to a spring and executing simple harmonic motion is given by x = 2 × 10^-2 π t metres. The time at which the ma - Physics MCQ AIEEE 2007 2026 | ExamTest.live

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The displacement of an object attached to a spring and executing simple harmonic motion is given by x = 2 \times 1 0^{- 2} cos π t metres. The time at which the maximum speed first occurs is:

Solution & Step-by-step Explanation

The displacement is given by x = A cos ω t, where A = 2 \times 1 0^{- 2} m and ω = π rad/s .The velocity v is the derivative of displacement with respect to time: v = \frac{d x}{d t} = - 2 \times 1 0^{- 2} π sin π t The speed ∣ v ∣ is maximum when ∣ sin π t ∣ = 1 .The first time this occurs is when: π t = \frac{π}{2} t = \frac{1}{2} = 0.5 s

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The displacement of an object attached to a spring and executing simple harmonic motion is given by x = 2 \times 1 0^{- 2} cos π t metres. The time at which the maximum speed first occurs is:

0.5 s

0.75 s

0.125 s

0.25 s

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