The displacement-time graphs of two moving particles make angles of 30^ and 45^ with the x -axis as shown in the figure. The ratio of their respective velocity is:![image](https://pub-7faa453bd1ec4bf0a04cc031c6f058de.r2.dev/images/929147b2-2714-4434-8ff2-3d05f1d370c2.png)

The velocity v is given by the slope of the displacement-time graph ( v = ds/dt = θ ).Ratio of velocities v_1/v_2 = θ_1/θ_2 .Given θ_1 = 30^ and θ_2 = 45^ . v_1/v_2 = 30^/45^= 1/√(3)1 = 1/√(3) The ratio is 1 : √(3) .

The displacement-time graphs of two moving particles make angles of 30^ and 45^ with the x -axis as shown in the figure. The ratio of their respective - Physics MCQ NEET 2022 2026 | ExamTest.live

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The displacement-time graphs of two moving particles make angles of 3 0^{\circ} and 4 5^{\circ} with the x -axis as shown in the figure. The ratio of their respective velocity is:

A $3 : 1$
B $1 : 1$
C $1 : 2$
D $1 : 3$

Solution & Step-by-step Explanation

The velocity v is given by the slope of the displacement-time graph (v = \frac{d s}{d t} = tan θ).Ratio of velocities \frac{v _{1}}{v _{2}} = \frac{t a n θ _{1}}{t a n θ _{2}} .Given θ_{1} = 3 0^{\circ} and θ_{2} = 4 5^{\circ} . \frac{v _{1}}{v _{2}} = \frac{tan 3 0 ^{\circ}}{tan 4 5 ^{\circ}} = \frac{1/ 3}{1} = \frac{1}{3} The ratio is 1 : 3 .

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The displacement-time graphs of two moving particles make angles of 3 0^{\circ} and 4 5^{\circ} with the x -axis as shown in the figure. The ratio of their respective velocity is:

3 : 1

1 : 1

1 : 2

1 : 3

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The displacement-time graphs of two moving particles make angles of $3 0^{\circ}$ and $4 5^{\circ}$ with the $x$ -axis as shown in the figure. The ratio of their respective velocity is:

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The displacement-time graphs of two moving particles make angles of 30∘ and 45∘ with the x -axis as shown in the figure. The ratio of their respective velocity is:

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The displacement-time graphs of two moving particles make angles of $3 0^{\circ}$ and $4 5^{\circ}$ with the $x$ -axis as shown in the figure. The ratio of their respective velocity is: