The enthalpies of combustion of carbon and carbon monoxide are -393.5 and -283\ kJ mol^-1 respectively. The enthalpy of formation of carbon monoxide p - Chemistry MCQ AIEEE 2004 2026 | ExamTest.live

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The enthalpies of combustion of carbon and carbon monoxide are - 393.5 and - 283 kJ mol^{- 1} respectively. The enthalpy of formation of carbon monoxide per mole is:

Solution & Step-by-step Explanation

Reactions given: C (s) + O_{2} (g) \to CO_{2} (g); Δ H_{1} = - 393.5 kJ . CO (g) + \frac{1}{2} O_{2} (g) \to CO_{2} (g); Δ H_{2} = - 283 kJ . The enthalpy of formation of CO corresponds to: C (s) + \frac{1}{2} O_{2} (g) \to CO (g) . Using Hess's Law (Eq 1 - Eq 2): Δ H_{f} = Δ H_{1} - Δ H_{2} = - 393.5 - (- 283) = - 110.5 kJ/mol .

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The enthalpies of combustion of carbon and carbon monoxide are - 393.5 and - 283 kJ mol^{- 1} respectively. The enthalpy of formation of carbon monoxide per mole is:

110.5 kJ

- 110.5 kJ

- 676.5 kJ

676.5 kJ

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