The equation of a wave on a string of linear mass density 0.04 kg m^-1 is given by y = 0.02(m) [2π(t/0.04(s) - x/0.50(m))] . The tension in the string - Physics MCQ AIEEE 2026 | ExamTest.live

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The equation of a wave on a string of linear mass density 0.04 kg m^{- 1} is given by y = 0.02 (m) sin [2 π (\frac{t}{0.04 ( s )} - \frac{x}{0.50 ( m )})] . The tension in the string is:

Solution & Step-by-step Explanation

The wave speed v = \frac{ω}{k} .From the equation: ω = \frac{2 π}{0.04} and k = \frac{2 π}{0.50} . v = \frac{2 π /0.04}{2 π /0.50} = \frac{0.50}{0.04} = 12.5 m/s .Also, v = \frac{T}{μ} ⟹ T = μ v^{2} . T = 0.04 \times (12.5)^{2} = 0.04 \times 156.25 = 6.25 N .

Try it yourself before checking the explanation above.

The equation of a wave on a string of linear mass density 0.04 kg m^{- 1} is given by y = 0.02 (m) sin [2 π (\frac{t}{0.04 ( s )} - \frac{x}{0.50 ( m )})] . The tension in the string is:

4.0 N

12.5 N

0.5 N

6.25 N

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