The equilibrium constants K_P1 and K_P2 for the reactions X leftharpoons 2Y and Z leftharpoons P + Q , respectively, are in the ratio of 1 : 9 . If the degree of dissociation of X and Z be equal, then the ratio of total pressure at these equilibria is:

For reaction 1: X leftharpoons 2Y Total moles at equilibrium = (1-x) + 2x = 1+x . K_P1 = (2x)^2 P_1/(1-x)(1+x) = 4x^2 P_1/1-x^2 For reaction 2: Z leftharpoons P + Q Total moles at equilibrium = (1-x) + x + x = 1+x . K_P2 = x × x × P_2/(1-x)(1+x) = x^2 P_2/1-x^2 Ratio: _P1K_P2 = 4P_1/P_2 = 1/9 P_1/P_2 = 1/36

The equilibrium constants K_P1 and K_P2 for the reactions X leftharpoons 2Y and Z leftharpoons P + Q , respectively, are in the ratio of 1 : 9 . If th - Chemistry MCQ AIEEE 2026 | ExamTest.live

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The equilibrium constants K_{P 1} and K_{P 2} for the reactions X ⇌ 2 Y and Z ⇌ P + Q, respectively, are in the ratio of 1 : 9 . If the degree of dissociation of X and Z be equal, then the ratio of total pressure at these equilibria is:

A $1 : 36$
B $1 : 1$
C $1 : 3$
D $1 : 9$

Solution & Step-by-step Explanation

For reaction 1: X ⇌ 2 Y Total moles at equilibrium = (1 - x) + 2 x = 1 + x . K_{P 1} = \frac{( 2 x ) ^{2} P _{1}}{( 1 - x ) ( 1 + x )} = \frac{4 x ^{2} P _{1}}{1 - x ^{2}} For reaction 2: Z ⇌ P + Q Total moles at equilibrium = (1 - x) + x + x = 1 + x . K_{P 2} = \frac{x \cdot x \cdot P _{2}}{( 1 - x ) ( 1 + x )} = \frac{x ^{2} P _{2}}{1 - x ^{2}} Ratio: \frac{K _{P 1}}{K _{P 2}} = \frac{4 P _{1}}{P _{2}} = \frac{1}{9} \frac{P _{1}}{P _{2}} = \frac{1}{36}

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The equilibrium constants K_{P 1} and K_{P 2} for the reactions X ⇌ 2 Y and Z ⇌ P + Q, respectively, are in the ratio of 1 : 9 . If the degree of dissociation of X and Z be equal, then the ratio of total pressure at these equilibria is:

1 : 36

1 : 1

1 : 3

1 : 9

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The equilibrium constants $K_{P 1}$ and $K_{P 2}$ for the reactions $X ⇌ 2 Y$ and $Z ⇌ P + Q$ , respectively, are in the ratio of $1 : 9$ . If the degree of dissociation of $X$ and $Z$ be equal, then the ratio of total pressure at these equilibria is:

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The equilibrium constants KP1​ and KP2​ for the reactions X⇌2Y and Z⇌P+Q, respectively, are in the ratio of 1:9. If the degree of dissociation of X and Z be equal, then the ratio of total pressure at these equilibria is:

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Discussion

The equilibrium constants $K_{P 1}$ and $K_{P 2}$ for the reactions $X ⇌ 2 Y$ and $Z ⇌ P + Q$ , respectively, are in the ratio of $1 : 9$ . If the degree of dissociation of $X$ and $Z$ be equal, then the ratio of total pressure at these equilibria is: