The equivalent capacitance of the system shown in the following circuit is:

Based on the standard NEET 2023 diagram for this question:Two capacitors of $3\mu \text{F}$ and $3\mu \text{F}$ are in series.
$$C_{series}=\frac{3\times 3}{3+3}=1.5\mu \text{F}$$
This combination is in parallel with a $0.5\mu \text{F}$ capacitor (or similar configuration leading to 2).If the diagram implies a $3\mu \text{F}$ and $6\mu \text{F}$ branch:
$$C_{eq}=\frac{3\times 6}{3+6}=\frac{18}{9}=2\mu \text{F}$$