The escape velocity from the Earth’s surface is v . The escape velocity from the surface of another planet having a radius, four times that of Earth a - Physics MCQ NEET 2021 2026 | ExamTest.live

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The escape velocity from the Earth’s surface is v . The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is:

Solution & Step-by-step Explanation

The escape velocity v_{e} is given by: v_{e} = \frac{2 GM}{R} Mass M can be written in terms of density ρ as M = ρ \times \frac{4}{3} π R^{3} . v_{e} = \frac{2 Gρ \frac{4}{3} π R ^{3}}{R} = \frac{8}{3} Gρ π R^{2} v_{e} \propto R (when density is constant) For the new planet: R^{'} = 4 R \Rightarrow v^{'} = 4 v

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The escape velocity from the Earth’s surface is v . The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is:

3 v

4 v

v

2 v

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