The freezing point depression constant for water is 1.86^/m . If 5.00 g Na_2SO_4 is dissolved in 45.0 g H_2O , the freezing point is changed by -3.82^ - Chemistry MCQ Chemistry | ExamTest.live

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The freezing point depression constant for water is 1.8 6^{\circ} C/m . If 5.00 g Na_{2} SO_{4} is dissolved in 45.0 g H_{2} O, the freezing point is changed by - 3.8 2^{\circ} C . Calculate the van't Hoff factor for Na_{2} SO_{4} : (Molar mass of Na_{2} SO_{4} = 142 g/mol)

A $0.381$
B $2.05$
C $2.63$
D $3.11$

Solution & Step-by-step Explanation

Using the formula Δ T_{f} = i \times K_{f} \times m : Δ T_{f} = 3.8 2^{\circ} C m = \frac{5.00/142}{45.0/1000} = \frac{0.0352}{0.045} = 0.782 m 3.82 = i \times 1.86 \times 0.782 i = \frac{3.82}{1.454} \approx 2.63

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The freezing point depression constant for water is 1.8 6^{\circ} C/m . If 5.00 g Na_{2} SO_{4} is dissolved in 45.0 g H_{2} O, the freezing point is changed by - 3.8 2^{\circ} C . Calculate the van't Hoff factor for Na_{2} SO_{4} : (Molar mass of Na_{2} SO_{4} = 142 g/mol)

0.381

2.05

2.63

3.11

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The freezing point depression constant for water is $1.8 6^{\circ} C/m$ . If $5.00 g$ $Na_{2} SO_{4}$ is dissolved in $45.0 g$ $H_{2} O$ , the freezing point is changed by $- 3.8 2^{\circ} C$ . Calculate the van't Hoff factor for $Na_{2} SO_{4}$ : (Molar mass of $Na_{2} SO_{4} = 142 g/mol$ )

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The freezing point depression constant for water is 1.86∘C/m. If 5.00g Na2​SO4​ is dissolved in 45.0g H2​O, the freezing point is changed by −3.82∘C. Calculate the van't Hoff factor for Na2​SO4​: (Molar mass of Na2​SO4​=142g/mol)

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The freezing point depression constant for water is $1.8 6^{\circ} C/m$ . If $5.00 g$ $Na_{2} SO_{4}$ is dissolved in $45.0 g$ $H_{2} O$ , the freezing point is changed by $- 3.8 2^{\circ} C$ . Calculate the van't Hoff factor for $Na_{2} SO_{4}$ : (Molar mass of $Na_{2} SO_{4} = 142 g/mol$ )