The hybridization involved in complex $[\text{Ni}(\text{CN}{)}_4{]}^{2-}$ is: (Atomic number of $\text{Ni}=28$)

1. ${\text{Ni}}^{2+}$ configuration: $[Ar]3d^{8}4s^0$.2. ${\text{CN}}^{-}$ is a strong field ligand, causing pairing of the $3d$ electrons.3. Pairing $3d^8$ leaves one $3d$ orbital vacant.4. The vacant $3d$, $4s$, and two $4p$ orbitals hybridize to form $ds{p}^2$ hybrid orbitals, resulting in a square planar geometry.