The internal angle bisectors BI and CI of ∠B and ∠C of a ΔABC meet at point I. If ∠A=38
∘
, then what is ∠BIC equal to?

Point I is the intersection of internal angle bisectors, which means I is the incenter of ΔABC.
The standard property for the angle formed at the incenter is:

∠BIC=90
∘
+
2
1
​
∠A
Given ∠A=38
∘
, substitute this into the formula:

∠BIC=90
∘
+
2
38
∘

​

∠BIC=90
∘
+19
∘
=109
∘