The ionization enthalpy of hydrogen atom is 1.312 × 10^6 J/mol . The energy required to excite the electron in the atom from n = 1 to n = 2 is: - Chemistry MCQ AIEEE 2026 | ExamTest.live

mediumMCQAIEEE2026Chemistry

1 mark

The ionization enthalpy of hydrogen atom is 1.312 \times 1 0^{6} J/mol . The energy required to excite the electron in the atom from n = 1 to n = 2 is:

Solution & Step-by-step Explanation

Ionization energy is the energy required to move an electron from n = 1 to n = \infty . E_{\infty} - E_{1} = 1.312 \times 1 0^{6} J/mol .Since E_{\infty} = 0, E_{1} = - 1.312 \times 1 0^{6} J/mol .Energy at level n is E_{n} = \frac{E _{1}}{n ^{2}} .Energy required for n = 1 \to n = 2 is Δ E = E_{2} - E_{1} : Δ E = \frac{E _{1}}{2 ^{2}} - E_{1} = E_{1} (\frac{1}{4} - 1) = - \frac{3}{4} E_{1} Δ E = - \frac{3}{4} (- 1.312 \times 1 0^{6}) = 0.75 \times 1.312 \times 1 0^{6} = 9.84 \times 1 0^{5} J/mol

Try it yourself before checking the explanation above.

The ionization enthalpy of hydrogen atom is 1.312 \times 1 0^{6} J/mol . The energy required to excite the electron in the atom from n = 1 to n = 2 is:

8.51 \times 1 0^{5} J/mol

6.56 \times 1 0^{5} J/mol

7.56 \times 1 0^{5} J/mol

9.84 \times 1 0^{5} J/mol

Practice with timed mock tests and track your performance across Chemistry.