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easyMCQNEET 20172026Chemistry
4 marks (−1)

The IUPAC name of the compound is:
image

  1. A
    3-keto-2-methylhex-4-enal
  2. B
    5-formylhex-2-en-3-one
  3. C
    5-methyl-4-oxohex-2-en-5-al
  4. D
    3-keto-2-methylhex-5-enal

Solution & Step-by-step Explanation

image
1. Principal functional group is aldehyde (), so numbering starts from its carbon.2. The chain has 6 carbons ().3. Substituents: Methyl at , ketone (keto/oxo) at .4. Double bond (ene) starts at .Name: 2-methyl-3-oxohex-4-enal or 3-keto-2-methylhex-4-enal.

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The IUPAC name of the compound is:
image
A
3-keto-2-methylhex-4-enal
B
5-formylhex-2-en-3-one
C
5-methyl-4-oxohex-2-en-5-al
D
3-keto-2-methylhex-5-enal

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