The IUPAC name of the compound is:

- A3-keto-2-methylhex-4-enal
- B5-formylhex-2-en-3-one
- C5-methyl-4-oxohex-2-en-5-al
- D3-keto-2-methylhex-5-enal
Solution & Step-by-step Explanation

1. Principal functional group is aldehyde (), so numbering starts from its carbon.2. The chain has 6 carbons ().3. Substituents: Methyl at , ketone (keto/oxo) at .4. Double bond (ene) starts at .Name: 2-methyl-3-oxohex-4-enal or 3-keto-2-methylhex-4-enal.