The length of a simple pendulum executing simple harmonic motion is increased by 21\% . The percentage increase in the time period of the pendulum of - Physics MCQ AIEEE 2003 2026 | ExamTest.live

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The length of a simple pendulum executing simple harmonic motion is increased by 21% . The percentage increase in the time period of the pendulum of increased length is:

Solution & Step-by-step Explanation

Time period T = 2 π \frac{l}{g} ⟹ T \propto l .Let initial length be l . New length l^{'} = 1.21 l . T^{'} \propto 1.21 l = 1.1 l = 1.1 T Percentage increase = \frac{T ^{'} - T}{T} \times 100 = \frac{1.1 T - T}{T} \times 100 = 10% .

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The length of a simple pendulum executing simple harmonic motion is increased by 21% . The percentage increase in the time period of the pendulum of increased length is:

11%

21%

42%

10%

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