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The lengths of the three sides of a triangle are given as 3cm, 4cm and 5cm. The ratio of their corresponding altitudes to the opposite vertices will be:

  1. A
    3:4:5
  2. B
    9:8:7
  3. C
    20:15:12
  4. D
    5:4:3

Solution & Step-by-step Explanation

Let the sides of the triangle be a=3cm, b=4cm, and c=5cm.
Let the corresponding altitudes to these sides be h
a

, h
b

, and h
c

respectively.

The area (Δ) of a triangle can be expressed as:

Δ=
2
1

×base×altitude
Thus, we have:

Δ=
2
1

×a×h
a

=
2
1

×b×h
b

=
2
1

×c×h
c


This implies:

a×h
a

=b×h
b

=c×h
c

=2Δ
Therefore, the altitudes are inversely proportional to the sides:

h
a

:h
b

:h
c

=
a
1

:
b
1

:
c
1


h
a

:h
b

:h
c

=
3
1

:
4
1

:
5
1


To convert this into integer ratios, multiply each term by the LCM of 3,4, and 5, which is 60:

h
a

:h
b

:h
c

=(
3
1

×60):(
4
1

×60):(
5
1

×60)=20:15:12

Practice this question

Try it yourself before checking the explanation above.

The lengths of the three sides of a triangle are given as 3cm, 4cm and 5cm. The ratio of their corresponding altitudes to the opposite vertices will be:
A
3:4:5
B
9:8:7
C
20:15:12
D
5:4:3

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