The maximum number of students among whom $910$ pens and $1001$ pencils can be distributed in such a way that each student gets same number of pens and pencils, is:

To find the maximum number of students among whom the items can be distributed equally, we need to calculate the Highest Common Factor ($\text{HCF}$) of $910$ and $1001$.
Let's use the prime factorization method:

$$910=2\times 5\times 7\times 13$$

$$1001=7\times 11\times 13$$

The common prime factors are $7$ and $13$.

$$\text{HCF}(910,1001)=7\times 13=91$$

Thus, the maximum number of students is $91$.