The minimum energy required to launch a satellite of mass m from the surface of earth of mass M and radius R in a circular orbit at an altitude of 2R - Physics MCQ NEET (UG) 2024 2026 | ExamTest.live

mediumMCQNEET (UG) 20242026Physics

1 mark

The minimum energy required to launch a satellite of mass m from the surface of earth of mass M and radius R in a circular orbit at an altitude of 2 R from the surface of the earth is:

Solution & Step-by-step Explanation

Total energy at surface E_{1} = - \frac{G m M}{R} + K_{l a u n c h} Total energy in orbit E_{2} = - \frac{G m M}{2 r}, where r = R + 2 R = 3 R . E_{2} = - \frac{G m M}{2 ( 3 R )} = - \frac{G m M}{6 R} Energy required Δ E = E_{2} - E_{surface_potential} = - \frac{G m M}{6 R} - (- \frac{G m M}{R}) $ Δ E = \frac{G m M}{R} - \frac{G m M}{6 R} = \frac{5 G m M}{6 R} $

Try it yourself before checking the explanation above.

The minimum energy required to launch a satellite of mass m from the surface of earth of mass M and radius R in a circular orbit at an altitude of 2 R from the surface of the earth is:

\frac{5 G m M}{6 R}

\frac{2 G m M}{3 R}

\frac{G m M}{2 R}

\frac{G m M}{3 R}

Practice with timed mock tests and track your performance across Physics.