The mixture which shows positive deviation from Raoult’s law is:
- AEthanol + Acetone
- BBenzene + Toluene
- CAcetone + Chloroform
- DChloroethane + Bromoethane
Solution & Step-by-step Explanation
In Ethanol + Acetone, the strong hydrogen bonding in pure ethanol is weakened by acetone molecules. This increases the vapour pressure of the mixture compared to an ideal solution, resulting in positive deviation.Benzene + Toluene and Chloroethane + Bromoethane are nearly ideal.Acetone + Chloroform shows negative deviation due to new H-bond formation.