The molar solubility product of a salt A_2B_3 is K_sp . The solubility ' s ' is given in terms of K_sp by the relation: - Chemistry MCQ AIEEE 2004 2026 | ExamTest.live

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The molar solubility product of a salt A_{2} B_{3} is K_{s p} . The solubility ' s' is given in terms of K_{s p} by the relation:

Solution & Step-by-step Explanation

For salt A_{x} B_{y}, K_{s p} = x^{x} y^{y} s^{x + y} . For A_{2} B_{3}, x = 2 and y = 3 . K_{s p} = 2^{2} \times 3^{3} \times s^{2 + 3} = 4 \times 27 \times s^{5} = 108 s^{5} . s^{5} = \frac{K _{s p}}{108} . s = (\frac{K _{s p}}{108})^{1/5} . Note: The question text contains some typos in numbering/options, but following the logic of the source key.

Try it yourself before checking the explanation above.

The molar solubility product of a salt A_{2} B_{3} is K_{s p} . The solubility ' s' is given in terms of K_{s p} by the relation:

s = (\frac{K _{s p}}{128})^{1/4}

s = (\frac{K _{s p}}{108})^{1/5}

s = (256 K_{s p})^{1/5}

s = (128 K_{s p})^{1/4}

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