The molarity of a solution obtained by mixing 750 mL of 0.5 M HCl with 250 mL of 2 M HCl will be: - Chemistry MCQ JEE Main 2026 | ExamTest.live

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The molarity of a solution obtained by mixing 750 mL of 0.5 M HCl with 250 mL of 2 M HCl will be:

Solution & Step-by-step Explanation

Using the mixing formula: M_{1} V_{1} + M_{2} V_{2} = M_{R} (V_{1} + V_{2}) Where: M_{1} = 0.5 M, V_{1} = 750 mL M_{2} = 2.0 M, V_{2} = 250 mL V_{R} = 750 + 250 = 1000 mL $ M_{R} = \frac{( 0.5 \times 750 ) + ( 2.0 \times 250 )}{1000} $ M_{R} = \frac{375 + 500}{1000} = \frac{875}{1000} = 0.875 M

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The molarity of a solution obtained by mixing 750 mL of 0.5 M HCl with 250 mL of 2 M HCl will be:

1.00 M

1.75 M

0.975 M

0.875 M

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