The number of real solutions of the equation $x^2-3|x|+2=0$ is:

Let $|x|=t$. Since $x^2=|x{|}^2$, the equation becomes:
$$t^2-3t+2=0$$
$$(t-1)(t-2)=0$$
So, $t=1$ or $t=2$.Substituting back $t=|x|$:$|x|=1⟹x=1,-1$$|x|=2⟹x=2,-2$ There are 4 real solutions.