The number of $\sigma$ bonds, $\pi$ bonds and lone pair of electrons in pyridine, respectively are:

Pyridine (${\text{C}}_5{\text{H}}_5\text{N}$) structure:$\sigma$ bonds: $5$ $\text{C-C}$ bonds, $5$ $\text{C-H}$ bonds, and $1$ $\text{C-N}$ bond (Wait, in the ring there are $5$ $\text{C}$ and $1$ $\text{N}$, so $6$ ring bonds + $5$ $\text{C-H}$ bonds) $=11$ $\sigma$ bonds.$\pi$ bonds: There are $3$ double bonds in the resonance structure $=3$ $\pi$ bonds.Lone pairs: Nitrogen has one lone pair which is not involved in resonance (it's in an $s{p}^2$ orbital) $=1$ lone pair.Count: 11, 3, 1.