The population of a district increases by 4\% during the first year and decreases by 5\% during the second year. If the present population of the dist - Quantitative Aptitude MCQ Competitive Exam 2026 | ExamTest.live

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The population of a district increases by 4% during the first year and decreases by 5% during the second year. If the present population of the district is 494, 000, its population two years ago was:

Solution & Step-by-step Explanation

Let the population of the district two years ago be P . * After the first year's 4% increase, the population becomes: P \times (1 + \frac{4}{100}) = 1.04 P * After the second year's 5% decrease, the population becomes: 1.04 P \times (1 - \frac{5}{100}) = 1.04 P \times 0.95 We are given that this present population value equals 494, 000 : P \times 1.04 \times 0.95 = 494, 000 P \times 0.988 = 494, 000 P = \frac{494 , 000}{0.988} = \frac{494 , 000 , 000}{988} = 500, 000

Try it yourself before checking the explanation above.

The population of a district increases by 4% during the first year and decreases by 5% during the second year. If the present population of the district is 494, 000, its population two years ago was:

475, 000

500, 000

525, 000

600, 000

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