The population of a town 2 years ago was 62,500. Due to migration to cities, it decreases every year at the rate of 4% per annum. Find its present population.
- A55600
- B51600
- C57600
- D53600
Solution & Step-by-step Explanation
Let the population 2 years ago be P
0
=62,500.
The rate of decrease is R=4% per annum.
The present population (P) after n=2 years is given by:
P=P
0
(1−
100
R
)
n
P=62500×(1−
100
4
)
2
P=62500×(
100
96
)
2
P=62500×(
25
24
)
2
P=62500×
625
576
P=100×576=57600
Thus, the present population is 57,600.
0
=62,500.
The rate of decrease is R=4% per annum.
The present population (P) after n=2 years is given by:
P=P
0
(1−
100
R
)
n
P=62500×(1−
100
4
)
2
P=62500×(
100
96
)
2
P=62500×(
25
24
)
2
P=62500×
625
576
P=100×576=57600
Thus, the present population is 57,600.