The potential energy of a long spring when stretched by 2 cm is U . If the spring is stretched by 8 cm , the potential energy stored in it will be: - Physics MCQ NEET 2023 2026 | ExamTest.live

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The potential energy of a long spring when stretched by 2 cm is U . If the spring is stretched by 8 cm, the potential energy stored in it will be:

Solution & Step-by-step Explanation

The potential energy E stored in a spring is proportional to the square of its extension x : E = \frac{1}{2} k x^{2} ⟹ E \propto x^{2} Given: E_{1} = U for x_{1} = 2 cm x_{2} = 8 cm = 4 x_{1} $ \frac{E _{2}}{E _{1}} = (\frac{x _{2}}{x _{1}})^{2} = (4)^{2} = 16 $ E_{2} = 16 E_{1} = 16 U

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The potential energy of a long spring when stretched by 2 cm is U . If the spring is stretched by 8 cm, the potential energy stored in it will be:

2 U

4 U

8 U

16 U

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