The primary and secondary coils of a transformer have and turns respectively. If the magnetic flux linked with the primary coil is given by , where is in weber, is time in second and is a constant, the output voltage across the secondary coil is:
- A
- B
- C
- D
Solution & Step-by-step Explanation
Voltage across primary .Using transformer ratio: $
\phi V_s = N_s \frac{d\phi}{dt} = 1500 \times 4 = 6000\,\text{V} 120\text{ V} V_p = 4\text{ V} V_s = 4 \times \frac{1500}{50} = 120\text{ V} \phi$ is flux per turn).
\phi V_s = N_s \frac{d\phi}{dt} = 1500 \times 4 = 6000\,\text{V} 120\text{ V} V_p = 4\text{ V} V_s = 4 \times \frac{1500}{50} = 120\text{ V} \phi$ is flux per turn).